[tex]x = \sqrt{12} + \sqrt{27} - \sqrt{48} [/tex]
[tex]y = \sqrt{ \sqrt{9} } - ( - \sqrt{3}) [/tex]
Hasil dari xy adalah ...
➩ Diketahui :
[tex]\sf \tt x = \sqrt{12} + \sqrt{27} - \sqrt{48} [/tex]
[tex]y = \sqrt{ \sqrt{9} } - ( - \sqrt{3}) [/tex]
➩ Ditanya :
[tex]\sf \tt hasil \: dari \: nilai \: xy \: ?[/tex]
➩ Jawab :
- Nilai X
[tex]\sf \tt x = \sqrt{12} + \sqrt{27} - \sqrt{48} [/tex]
[tex]\sf \tt x = \sqrt{4×3} + \sqrt{9×3} - \sqrt{16 × 3} [/tex]
[tex]\sf \tt x = (2 × \sqrt{3}) + (3× \sqrt{3}) - (4× \sqrt{ 3}) [/tex]
[tex]\sf \tt x = 2 \sqrt{3}+ 3 \sqrt{3} - 4 \sqrt{ 3}[/tex]
[tex]\sf \tt x = (2 +3-4)\sqrt{3}[/tex]
[tex]\sf \tt x = (5-4)\sqrt{3}[/tex]
[tex]\sf \tt \bold{x = \sqrt{3}}[/tex]
- Nilai y
[tex]\sf \tt y = \sqrt{ \sqrt{9} } - ( - \sqrt{3}) [/tex]
[tex]\sf \tt y = \sqrt{ 3 } - ( - \sqrt{3}) [/tex]
[tex]\sf \tt y = \sqrt{ 3 } + \sqrt{3} [/tex]
[tex]\sf \tt y = (1+1)\sqrt{ 3 }[/tex]
[tex]\sf \tt y = (2)\sqrt{ 3 }[/tex]
[tex]\sf \tt \bold{y = 2\sqrt{3}}[/tex]
- Nilai xy
[tex] \sf \bf xy =Nilai \: x \: . \: Nilai \: y[/tex]
[tex]\sf \bf xy = \sqrt{3} \: . \: 2 \sqrt{3}[/tex]
[tex]\sf \bf xy=2 × ( \sqrt{3} × \sqrt{3} )[/tex]
[tex]\sf \bf xy=2 × \sqrt{3 × 3}[/tex]
[tex]\sf \bf xy = 2 × \sqrt{9}[/tex]
[tex]\sf \bf xy = 2 × 3[/tex]
[tex]\bold{\underline{\boxed{\pink{\sf \bf \tt xy = 6}}}}[/tex]
#BelajarBersamaBrainly
Jawaban:
x = √12 + √27 - √48
= √4.3 + √9.3 - √16.3
= 2√3 + 3√3 - 4√3
= 5√3 - 4√3
= √3
y = √√9 - (-√3)
= √3 - (-√3)
= √3 + √3
= 2√3
xy = √3 . 2√3
= 2√3.3
= 2√9
= 2.3
= 6
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