jika f(x)=(2x-1)²(x-3) nilai f{}'(-1)=
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Jawaban:
12x²-32x+13
Masukkan -1:
= 12(-1)²-32(-1)+13
= 12+32+13
= 57
Penjelasan dengan langkah-langkah:
f(x)= (2x-1)²(x-3)
= (4x²-4x+1)(x-3)
Turunannya:
= (4x²-4x+1)'(x-3)+(4x²-4x+1)(x-3)'
= (8x-4)(x-3)+(4x²-4x+1)(1)
= 8x²-28x+12+4x²-4x+1
= 12x²-32x+13
Masukkan x= -1, diperoleh 57.
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